4.3+Finding+the+Perimeter

MP. November 4, 2008  Math 8D Day 24 **Problem 4.3 Finding the Perimeter:** The perimeter of triangle ABC is 75cm² I got this by finding the length of legs A and B then using the Pythagorean Theorem. To get leg A I used the length 8 from AD already given to get 16for the leg. To get leg B I used the length of AC (16) X 2 = 32 for leg Be Then I used this to get the last leg. 16² + ?² = 32²    256 + ? = 1024   256 - 256 + ? = 1024 – 256   ? = 768   √768 = 27.712812921102036696439141464094  So the last leg was equal to about 27. To find the perimeter just add the side lengths. By doing this, 27 + 16 + 32 I got the answer 75. //**1. Find the area of triangle ABC. Explain your reasoning.**//
 * Follow up 4.3:**

The Area of triangle ABC is 256cm². I got this by using the method ½ base X height = area of a triangle. Which was 16 X 0.5 X 32 = 256. The area of triangle ACD is 55.4 cm² The area of triangle BCD is 196.3 cm²
 * //2. Find the areas of triangle ACD and triangle BCD.//**